Question

A wire carries a current of 0.1A for 20sec of the potential diff bet'n the two ends the wire is 10v find the work done?

Answer 1

Answer:

20 J

Explanation:

Given:-

A = 0.1

t = 20s

V = 10

W = ?

A=Q/t

0.1 = Q/20

Q = 20 × 0.1

Q = 2 C

now,

V = W/Q

10 = W / 2

W = 20 J