A wire carries a current of 0.5A when a potential difference of 1.5V is applied across it. when is its resistance
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Wire with current 0.5 A
And potential difference 1.5V
Now we know V=IR
So R = V/I
R= 3
Conductance = 1/3
=> 0.333 ohm inverse or mho.
Wire of length = 3m
Area = 5.4 m2
Resistance = 3ohm
So r = rho 3/5.4
3 = rho 3/5.4
Hence rho = 5.4
So conductivity = 1/5.4
Hope it will help you.
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