A wire carrying a steady current is first bent in form of a circular coil of one turn and then in form of a circular coil of two turns. Fine the ratio of magnetic fields at the centers of the two coils. 2 marks
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Answer:
Case 1:
Number of turns =1
Current = I
Length of wire = l
radius= 2πl. =r1 (1)
Case 2:
Number of turns = n
Current = I
Length = l
radius= 2πnl =r2
Using relation:
B= 2rμ0nI
B2B1=2r1μ0I×μ0nI2r2
=nr1r2=2πnl×n1×l2π=n/21
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