Physics, asked by kitoo2004, 11 months ago

A wire carrying a steady current is first bent in form of a circular coil of one turn and then in form of a circular coil of two turns. Fine the ratio of magnetic fields at the centers of the two coils. 2 marks

Answers

Answered by shiuli812249
0

Explanation:

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Answered by madhokyash75
0

Answer:

Case 1:

Number of turns =1

Current = I

Length of wire = l

radius= 2πl. =r1    (1)

Case 2:

Number of turns = n

Current = I

Length = l

radius= 2πnl =r2

Using relation:

B= 2rμ0nI

B2B1=2r1μ0I×μ0nI2r2

=nr1r2=2πnl×n1×l2π=n/21

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