a wire connected to the power supply of 230 v has power dissipation p1.suppose the wire is cut into two equal pieces and connected parallel to the same power supply.in this case power dissipation is p2.the ratio p2÷p1 is
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Answer:Let us assume, initially Resistance of wire = R and Voltage drop acoss it=V=220 Volt
Then, P1 = V2/R
When Wire is cut down into two pieces then each wire would have resistance R/2.
Now equivalent resistance of wire connected in parallel = R/4
Then, P2= V2/(R/4)= 4V2/R = 4P1
Hence, P2:P1 = 4
Explanation:
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