Question

A wire extends by 1 mm when a force a applied. Double the force is applied to another wire of some material and length but half the radius of cross-section. The elongation of the wire in mm will be

Answer 1

Answer:

As we know

I proportional to F / r²

Hence ,

I2/I = F2 × (r1)² / F1 × (r2)² = 2 × 2² = 8

So the total length is 8 mm