Physics, asked by ananyasinha6509, 1 year ago

A wire fixed at the upper end stretches by length l by applying a force f. The work done in stretching is

Answers

Answered by mohmmedsufiyanali19
7

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Work done is equal to 1/2 × stress × strain × volume U=1/2 × F/A × ∆l/l × AL = 1/2 × f ∆l ATQ = 1/2FL

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Answered by duragpalsingh
3

Answer:

Work done in stretching is Fl / 2 J

Explanation:

Given,

A wire fixed at the upper end stretches by length l by applying a force F.

To find: The work done in stretching is

Solution:

The work done in stretching is equal to half of the product of stretching force and the increase in length.

or, Work done = (1/2) * stretching force * increase in length

or, Work done = (1/2) * F * l

or, Work done = Fl / 2

Therefore, Work done in stretching is Fl / 2 J

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