a wire forming a rectangle of dimensions 9 cm and 6.4 cm, is stretched and bent again to form a circle. what would the diameter of the circle.
Answers
Answered by
30
Lets first find the length of the wire .
length of wire = perimeter of rectangle formed
length of wire = 2 ( 9 + 6.4 ) [ since perimeter of rectangle = 2 ( length + breath ) ]
length of wire = 2 × 15.4 = 30.8 cm
same wire is use to create a circle.
so circumference of circle = length of wire = 30.8 cm
circumference of circle = 2πr [ where r is radius and π = 22/7 ]
⇒ 30.8 = 2 × 22/7 × r
⇒( 30.8 × 7 ) /44 = r
⇒ r = 4.9 cm
and diameter = 2r = 2 × 4.9 = 9.8 cm
hence diameter of circle formed = 9.8 cm
Answered by
11
Answer:176cm,42.42m
Step-by-step explanation:Given,r=28cm
Distance traveled in 1 revolution =circumference.
2×22/7×28=circumference
176cm=circumference
Thus,distance travelled in 24 revolutions=176cm×24=4242cm.
Attachments:
Similar questions