Question

A wire frame is in rectangular shape which is 18 cm long and 10.6 cm broad. If the wire is reshaped in the circular shape, find the diameter of the circle. (assume pi is 22/7)

Answer 1

Solutions :-

Given :
A wire frame is in rectangular shape which is 18 cm long and 10.6 cm broad.

Find the perimeter :-

Perimeter of rectangle = 2(Length + Breadth)
= 2(18 + 10.6) cm
= 2 × 28.6 cm
= 57.2 cm


Let the diameter of circle be d

Find the diameter of of the circle :-

Circumference/Perimeter = πd
=> 57.2 = 22/7 × d
=> 57.2 × 7 = 22d
=> 400.4/22 = d = 18.2


Hence,
Diameter of the wire which is reshaped in the circular shape = 18.2 cm

Answer 2

Solutions :-

We have,
Length = L = 18 cm
Radius = B = 10.6 cm


Perimeter of rectangular shaped wire = 2(L + B)
= 2(18 + 10.6) cm
= (2 × 28.6) cm
= 57.2 cm


Assuming the diameter of circle be d

We know that,
Circumference = πd
=> 57.2 = 22/7 × d
=> 57.2 × 7 = 22d
=> 400.4/22 = d = 18.2


Answer :
18.2 cm is the Diameter of the circular shape wire.