Math, asked by generalnishant7, 1 year ago

A wire frame is in rectangular shape which is 43 cm long and 47 cm broad. If the wire is reshaped in a semi-circular shape as shown below. The radius of the semi circle will be ______ cm. (assume π = 22/7

Answers

Answered by shanu6944
4

perimeter of rectangle = circumference of circle

2 (l+b) = 2


shanu6944: sorry
shanu6944: your answer is 180=2×22/7×r/2 180=22/7×r r= 180×7/22 r=57.27
Answered by arunkumar33
13

perimeter of rectangle = perimeter of semicircle

2(l+b) = 1/2*2πr

2(43+47) = 22/7*r

2*90*7/22 = r

90*7/11 = r

630/11 = r

57.27 = r

PLZZ MARK AS BRAINLIEST


arunkumar33: tnx a lot
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