A wire given material having length and area of cross section a has a resistence of 4 ohm . what would be the resistence of another wire of the same metirial having the length 1/2 and area of cross-section to a?
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Answer:
2
Explanation:
SInce L is Halved ,Therefore.
R = (rho)*l/a => R(dash) = 1/2(Rho*l/a)
Therefore New resistance will be 2
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