Question

A wire had resistance of 20 ohm .it was
melted and reduced to one-fifth of its
original length and is
d its cross section area was
doubled by gogi. Find its new Resistance ​

Answer 1

Step-by-step explanation:

R = ρ* L/A

R ∝ L And R ∝ 1/A

here, length is reduced to 1/5 times so resistance also reduced to 1/5 times

so, resistance is 20/5 Ω = 4 Ω

Again, Area is doubled so resistance get half.

so, New resistance is 4/2Ω = 2Ω

So, plz mark me as brainliest answer.