Question

A wire has a diameter of 0.5 mm and a resistivity of 1.6*10power-6 ohm cm . how much of this wire would be required to make a 10ohm coil

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Answer 1

Answer:

Step-by-step explanation:

DIAMETER , D= 0.5 MM

                       = 0.5*10⁻³M

RADIUS , r = D/2

                  = 0.5*10⁻³/2

                  = 0.25*10⁻³M

AREA OF THE WIRE, A= πr²

                                     = 3.14*(0.25*10⁻³)²

                                     = 0.196*10⁻³ M²

RESISTANCE , R= 10 OHM

RESISTIVITY ,ρ = 1.6*10⁻⁶ OHM CM

                          = 1.6*10⁻⁶*10⁻² OHM M

                          = 1.6*10⁻⁸ OHM M

LENGTH , L =?

FORMULA:

R = ρ* L/A

10 = 1.6*10⁻⁸*L/0.196*10⁻³

L = 10*0.196*10⁻³/1.6*10⁻⁸

L = 1.96*10⁻³*10⁺⁸/1.6

L = 1.225*10⁵ M.

HOPE THIS HELPS.