Physics, asked by priya024, 11 months ago

A wire has a non-uniform cross-section as shown in figure. A steady current flows through it. The drift
speed of electrons at point P and Q is Vp and Vq​


priya024: Sorry I could not send the fig
ItzPrincessNk: See I have Attached the figure

Answers

Answered by ItzPrincessNk
9

Answer:

Explanation:

we know formula ,

i = neaved

where n is number of electrons per unit volume , e is the charge of an electron , a is the cross section area of wire , i is current through wire and vd is the drift speed of electrons .

e.g.,

therefore drift speed is inversely proportional to cross section area. e.g., if we increase the cross section area , drift speed will decrease.

here, from A to B cross section area increases.

hence, drift speed decreases from A to B.

Hence, decreases is correct.

Note : Please try to post full question.But I have attached this question picture Have A look please

Attachments:

priya024: Actually I have not much idea about this app. I don't even know how to send the fig. I tried it but could not. I am sorry
sonal9939: okkk
sonal9939: no problem
sonal9939: but send full question so that it may easy to solve
priya024: I have installed this app recently and so I don't know how to use it.
sonal9939: okk
priya024: But yours fig is wrong
priya024: The given points are P and Q
priya024: The points are inside the wire
priya024: I got the ans. Vp>Vq
Answered by AkshayCV10
2

Answer:

Explanation:

drift velocity proportional to 1/area of Cross section..

ie,larger the area slower will be the speed of electron...

therefore; Vp > Vq

Ans:C

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