A wire has a resistance 10 ohm it is stretched by one tenth of the original length then its resistance will be what
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Explanation:
Let resistance of a conductor = pL/A
Where p is the resistivity of the material, L is thelength and A is the cross sectional area.
Lets assume the wire is cylindrical.
Volume ofa cylinder = V= r^2 x h
Where r is the radius and h is the height.
Here, A = Tr^2 and h =L
So, V = A*L
When you are stretching the volume will remain thesame
So V= AL = Ax(1.1)L (stretching by 10%)
Thus A = V/(1.1L) = 0.909A
So new resistance = pL'/A' = px1.1L/(0.909xA) =1.21R 12.10
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