A wire has a resistance of 10Ω. It is melted and drawn into a wire of half of its length. Calculate the resistance of the new wire. What is the percentage change in its resistance?
Pls Answers UwU
Answers
Answered by
3
Answer:
75%
Explanation:
Now, since the volume of the wire remains the same even after melting it.
Volume of wire before melting = Volume of wire after melting
Volume = Area * height
R is directly proportional to length.
Let new resistance be R'
R' = R/4
Change in resistance = R - R' => R - R/4 = 3R/4
% of change = 3/4 * 100 = 75%
Similar questions