A wire has a resistance of 16 ohm it is drawn to double its length and then cut it into four equal parts these parts are connected in parallel and series find new resistance
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Answer:
4
Explanation:
consider volume to be equal in both the cases
V1 = V2
so A1 * l1 = A2 * l2
since the length has been doubled l2= 2l1
it implies A1= 2A2
resistance = restivity *length /area
new res/prev res = 2 * length / (A1/2)
length /A1
new res = prev res * 4
which implies new resistance to be 64 ohms
since you have cut into 4 equal parts now each wire resistance would be 16 ohms each
now 4 wires of 16 ohms are connected into parallel
therefore equivalent resistance is 16/4 which is 4 ohms
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