A wire has a resistance of 16 ohms. It is melted and drawn into a wire of half of its original length. What is the resistance of the new wire? solve this full explanation
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In both the cases, the volume of the wire is same. So
V=Al=A'l'orA'=All'=All/2=2A
Now R=ρlA
and R'=ρl'A'=ρ×(1/2)2A=14=ρlA=R4
∴R'=164=4Ω
% decrease in resistance
=R−R'R×100=16−416×100=75%
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