Question

A wire has resistance of 10 ohm if it is stretched by one tenth of its original length then its resistance will be (show with calculation)
1.11 ohms
2.9 ohms
3.10 ohms
4.12.1 ohms​

Answer 1

Answer:

1st option- 11 ohms

Explanation:

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Answer 2

Explanation:

The resistance, R, of a wire of length l is given by,

R = ρl/A

Now if the wire is stretched keeping the volume intact then:

R = ρl²/V

Now R ∝ l², According to the question, we get,

R2 / R1 = (l2 / l1 )²

But R1 = 10Ω, l2/l1 = 11/10

=> R2/10 = 121/100

=> R2 = 12.1 Ω

Hence your answer is 12.1 Ω....