Physics, asked by AyushmanDas1841, 10 months ago

A wire has resistance of 2.5 ohm at 28 degree centigrade and a resistance of 2.9 ohm at 100 degree
centigrade The temperature coefficient of resistivity of material of the wire is
O
106 x 10-3
o 3.5% 10-2
2.22 x 10-3
O
3.95 x 10^-2​

Answers

Answered by Anonymous
4

Question: A wire has a resistance of 2.5 Ω at 28C and a resistance of 2.9 Ω at 100°C. The temperature coefficient of resistivity of material of the wire is?

Given: A wire has a resistance of 2.5 Ω at 28°C and a resistance of 2.9 Ω at 100°C.

To find: The temperature coefficient of resistivity of material of the wire.

Solution: 2.22\times 10^{-3} °C^{-1}

Step by Step Explanation:

R_2_8=2.5\\R_1_0_0=2.9

ΔR=\alphaθR_2_8°C

2.9-2.5=\alpha \times(100-28)\times2.5\\\alpha =2.22\times10^{-3}

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