A wire have resistance =10 ohm and if its diameter is doubled what is new resistance by how much times it decreases or increases
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Resistance= Resistivity x length/area
When the wire is stretched to double the length , the area of cross section gets reduced to half.
So
New Resistance = Resistivity x 2length/area/2
I.e,
New resistance = (Resistivity x area/length)x4
i.e, New resistance = Resistance x 4
So when the wire is stretched, the resistance multiplies by four times.
When the wire is stretched to double the length , the area of cross section gets reduced to half.
So
New Resistance = Resistivity x 2length/area/2
I.e,
New resistance = (Resistivity x area/length)x4
i.e, New resistance = Resistance x 4
So when the wire is stretched, the resistance multiplies by four times.
Dr33432:
No its wrong right answer is one sixteenth
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