Question

A wire have resistance of 90 Ohm is bent in the form of a equletral traingle. fine the resistance.between his two end of vertices .??

Answer 1

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Answer 2

A wire have resistance of 90ohm is bent in the form of a equilateral triangle.We know that the equilateral triangle has three equal sides
So this 90 ohm resistance will be get divided into three equal parts therefore the resistance between any two ends will be:-90/3=30 Ohm.
That is 30×3=90 Ohm.

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