Math, asked by supti2708, 4 months ago

a wire having a mass if 1kg possess a resistance of 0.1 ohm . of the resistivity of material of wire is 10^-7ohm meter and density of material of wire is 10^4kg/m^3, then length of wire is​

Answers

Answered by brainlyB0SS
0

GIVEN

Mass of the wire = 1 kg

Resistance = 0.1 ohm

Resistivity of the wire = 10^-7

Density of the material = 10⁴ kg/m³

TO FIND

Length of the wire.

SOLUTION

Volume = m/d =1/ 10⁴ = 10^-4 m³

Where m = mass of wire

d = density

Volume = A*l = 10⁴

Where A = area

l = length of wire

Resistance = pl/A

Where p = resistivity

l = length of wire

A = area of wire

0.1 = 10^-7 * l/ A

Since A = 10^-4/l, Putting the value of A we get:

0.1 = 10^-7 * l²/ 10^-4

100 = I²

l = 10 m

Answered by abhi178
1

Given info : a wire having a mass if 1 kg possess a resistance of 0.1 ohm . of the resistivity of material of wire is 10^-7ohm meter and density of material of wire is 10⁴ kg/m³.

To find : The length of wire is .....

solution : mass of the wire, m = 1 kg

density of the wire , d = 10⁴ kg/m³

so the volume of the wire , V = m/d = 1/10⁴ = 10¯⁴ m³ .......(1)

we know, R = ρl/A

⇒R = ρl²/Al

⇒R = ρl²/V

where R is resistance of wire, l is length of wire and A is cross sectional area of the wire.

here, R = 0.1 Ω

ρ = 10^-7 Ω m

V = 10¯⁴ m³

so, 0.1 = 10^-7 × l²/10¯⁴

⇒100 = l²

⇒l = 10 m

Therefore the length of the wire is 10m.

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