a wire having resistance of 20 ohm, carrying current of 9 ampere. what is the potential difference across its ends?
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Answered by
1
Explanation:
V=IR
I=9A
R=20OHM
V=20×9=180V
Answered by
1
Given :
• Resistance = 20 Ohms
• Current = 9 A
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To Find :
• Potential difference across ends
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Solution :
Use Ohm's law :
⇒ V = IR
⇒V = 20 * 9
⇒ V = 180
➜ Potential difference is 180 V.
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