Question

A wire having resistance ‘R’ allows a current ‘I’ to pass through it when put across a
battery of voltage ‘V’. The wire is cut into 4 equal parts and the corresponding pieces are
joined in parallel to form a new resistor. Find the new resistance of the combination.
How much current would pass through each individual wire if the combination is put
across a battery of voltage ‘V’?

please only legitimate answers

Answer 1

The current through each part in the parallel combination will be one-fourth i.e. I/4

Explanation:

• When a wire of resistance R is divided into four equal parts the resistance of each part becomes one-fourth.
• So, the resistance of each part is R/4
• The resistance of the parallel combination is Requ.
• $\frac{1}{Requ} = \frac{1}{R/4} + \frac{1}{R/4} + \frac{1}{R/4}$  
• $Requ = \frac{R}{16}$
• Now, the current through the wire is R.
• So, the current through each part in the parallel combination will be one-fourth i.e. I/4
• Hence, the resistance of the combination is 1/16 th and the current through each part is 1/4 th.