Question

a wire in the form of a circle of radius 3.5 m is bent in the form of a rectangle, where length and breadth are in the ratio of 6:5 . what is the area of the rectangle?

Answer 1

hey! I am not describing the whole but I can say how it can be solved.
let's begin
from the radius of the circle find the circumference
and now,the circumference would be equal to the perimeter of the rectangle.
now with the help of perimeter find the sides and then find the area of the rectangle

if you find my explanation helpful
then mark me as brainliest

Answer 2

Answer:

Area of Rectangle is 30 m².

Step-by-step explanation:

Given: Radius of circle, r = 3.5 m

           Ratio of length and breadth = 6 : 5

To find: Area of Rectangle

Length of wire = Circumference of Circle =  Perimeter of Rectangle

let length  = 6x & Breadth = 5x

Circumference of Circle =  Perimeter of Rectangle

$2\pi r=2\times(length+breadth)$

$2\times\frac{22}{7}\times3.5=2\times(6x+5x)$

$2\times22\times0.5=2\times(11x)$

$2\times0.5=x$

x = 1

⇒ Length = 6 m & Breadth = 5 m

Area of Rectangle =  Length × Breadth = 6 × 5 = 30 m²

Therefore, Area of Rectangle is 30 m².