A wire in the form of a rectangle 18.7 cm long and 14.3 cm wide is reshaped and bent into the form of a circle. Find the radius of the circle so formed.
Answers
Answered by
414
perimeter of rectangle = (18.7+14.3)×2 = 33×2 = 66 cm
circumference of circle = perimeter of rectangle
2πr = 66
r = 66/2π
r = 66×7/2×22
r = 21/2
r = 10.5 cm
so,
radius of circle = 10.5 cm
circumference of circle = perimeter of rectangle
2πr = 66
r = 66/2π
r = 66×7/2×22
r = 21/2
r = 10.5 cm
so,
radius of circle = 10.5 cm
Answered by
153
Perimeter of rectangle= circumference of circle
2(l+B)=2πr
2(18.7+14.3)=2×22/7×r
33=22/7r
r=33×7/22=21/2=10.5 cm
HOPE IT WAS HELPFUL
2(l+B)=2πr
2(18.7+14.3)=2×22/7×r
33=22/7r
r=33×7/22=21/2=10.5 cm
HOPE IT WAS HELPFUL
Similar questions