Question

A wire in the form of a square
encloses an area of 144 cm2. How
much area is enclosed if the same wire
is bent in the form of a rectangle of
length 16 cm ?​

Answer 1

Answer:

Step-by-step explanation:

Given : area of square is 144 cm^2

 Let length of the side is a

hence area = $a^{2}$

⇒ $a^{2}$ = 144

⇒a = $\sqrt{144}$

⇒a= 12cm

which implies perimeter of the square is 4*12 = 48 cm

hence perimeter of the rectangle is 48cm = 2*(length + breadth)

                                                                       = 2*(16 + breadth)

             ⇒  48 = 2*(16 + breadth)

                ⇒ 24 = 16 + breadth

               ⇒ breadth = 8 cm

area of rectangle = length * breadth

                             =16 * 8

                              = 128 $cm^{2}$