Question

A wire in the form of a square with side 22 CM. Its reshaped and bent into the form of a circle. Calculate the area of square. (pi=22/7)

Answer 1

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Here is your answer.

Side of Square = 22cm

Area of Square = ${(side)}^{2}$

$= {(22)}^{2} \\ = 484 {cm}^{2}$
Perimeter of Square = 4 × side
$= 4 \times 22 \\ = 88cm$
Perimeter of Square = Circumference of circle

So,
$2\pi r = 88 \\ \\ r = \frac{88 \times 7}{2 \times 22} \\ \\ r = 14cm$
Now, Area of circle = $\pi {r}^{2}$

$= \frac{22 \times 14 \times 14}{7} \\ \\ = 616 {cm}^{2}$
Therefore, Area of circle is $616 {cm}^{2}$

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Answer 2

Question: The correct question is "A wire in the form of a square with side 22 CM. Its reshaped and bent into the form of a circle. Calculate the area of the circle formed by the wire."

Solution:

Area of the circle is 616 cm².

• A wire is in the form of a square with side of the square is 22 cm.

Perimeter of the square = 4 × side

Perimeter = 4 × 22 = 88 cm

• Now the wire is bent into a circle , Perimeter of the wire will be the same.

• Perimeter of the square = Perimeter of the circle

88 = Perimeter of the circle

2πr = 88

2×(22/7)×r = 88

r = 14 cm

Radius of the circle with the wire is 14 cm.

Now arer of the circle is πr².

• Now, area = (22/7)×14×14 = 616 sq. cm
• Area of the circle is 616 sq. cm.