Question

A wire in the form of an equilateral triangle of side 40 cm is covered into a square . Find the area of the square to formed.​

Answer 1

Answer:

side =40cm

therefore perimeter of the triangle =perimeter of the square=3x40cm=120cm

We know that, perimeter of a square = 4xside.

let the side of the square be a.

therefore,4xa=120

or,a=120/4=30

therefore ,side of the square =30cm

therefore, its area =30x30 sq.cm =900sq.cm.

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Answer 2

Answer:

${900 \: cm}^{2}$

Step-by-step explanation:

Equilateral triangle has all sides equal. Therefore, its Perimeter is-

$40 \times 3 = 120cm$

Now, when the wire is bent into a shape of a square, its length does not change, i.e., remains 120 cm.

Now, a square has 4 sides of equal length. So length of each side will be-

$120 \div 4 = 30cm$

So, now we have side of square as 30 cm. Therefore, area of square is

$(side)^{2} \\ = (30)^{2} \\ = 900 \: cm^{2}$

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