Question

A wire in the form of rectangle 18.7cm long and 14.3cm wide is reshaped and bent into the form of a circle . find the radius of the Circle so formed?​

Answer 1

Answer:

Perimeter of rectangle=(18.7+14.3)×2=33×2=66 cm

Circumference of circle= perimeter of rectangle

⇒2πr=66

⇒r=

2π

66

⇒r=

2

66

×

22

7

⇒r=

2

21

∴r=10.5 cm

So, radius of circle =10.5 cm

Step-by-step explanation:

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Answer 2

Given:-

length of rect =18.7cm

breadth =14.3 cm

Solution:-

${\boxed{\pink{perimeter=2(l+b) units}}}$

=2(18.7+14.3)cm

=2×33cm

=66cm

perimeter of rect.=circumference of circle

therefore, Circumference of circle=66cm

that means,

$2 \pi r = 66 \\ 2 \times \dfrac{22}{ 7} \times r = 66 \\ r =\dfrac{ 66 \times 7}{ (22 \times 2)} \\ r =\dfrac{ 21 }{ 2 }\\ r = 10.5$

$\sf\therefore \: radius \:of \:circle=10.5cm$