Question

A wire in the form of rectangle of 180.7cm and 140.3cm wide is bent into a circle.find the radius of circle so formed

Answer 1

perimeter of rectangle=circumference of circle
2(l+b)=2πr
180.7+140.3=22/7×r
321=22/7×r

r=321×7/22
r=2247/22
r=102.13

Hope this will help.

Answer 2

Answer:

The radius of circle is 102.14 cm.

Step-by-step explanation:

The dimensions of a rectangle are 80.7cm and 140.3cm.

The perimeter of a rectangle is

$P=2(l+w)$

$P=2(180.7+140.3)$

$P=642$

The rectangle of 180.7cm and 140.3cm wide is bent into a circle. It means the perimeter of rectangle is equal to the circumference of the circle.

$2\pi r=642$

$\frac{22}{7}\times r=321$

$r=321\times \frac{7}{22}=102.1363\approx 102.14$

Therefore the radius of circle is 102.14 cm.