a wire in the shape of a rectangle its length is 40 cm and breadth is 22 CM if the same wire is repent in the shape of a square what will be the measure of each side also find which shape enclose more area
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Answered by
8
perimeter=2(40+22)
=124
perimeter of square =that of rectangle
4s=124
s=31
Area of square =s2
=31×31
=961
area of rectangle =40×22
=880
therefore, wire encloses more space when in
=124
perimeter of square =that of rectangle
4s=124
s=31
Area of square =s2
=31×31
=961
area of rectangle =40×22
=880
therefore, wire encloses more space when in
Answered by
12
Length of rectangle= 40cm
Breadth of rectangle= 22cm
Perimeter of rectangle=2(l+b)
=> 2(40+22)
=>2×62
=>124 cm
As rectangle and square are made up of same piece of wire. Therefore their perimeter will be same
Perimeter of square= 4 ×side
=>4×side= 124
=>side=124/4
=>Side=31 cm
Area of rectangle = l×b
=>40×22
=>880 square cm
Area of square= side ×side
=>31×31
=>961
Therefore square encloses more area.
Breadth of rectangle= 22cm
Perimeter of rectangle=2(l+b)
=> 2(40+22)
=>2×62
=>124 cm
As rectangle and square are made up of same piece of wire. Therefore their perimeter will be same
Perimeter of square= 4 ×side
=>4×side= 124
=>side=124/4
=>Side=31 cm
Area of rectangle = l×b
=>40×22
=>880 square cm
Area of square= side ×side
=>31×31
=>961
Therefore square encloses more area.
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