Math, asked by swetalipika, 1 year ago

A wire in the shape of a rectangle of length 18cm and width 15cm is reshaped and bent in the form of a circle find the radius

Answers

Answered by Anonymous
261
The wire is in the shape of rectangle
length = 18 cm
breadth = 15 cm

now the wire is bent into a circle

so

perimeter of rectangle = circumference of the circle

2(l+b) = 2πr
2(18 +15)     =  2πr
2
×33 = 2πr
66 = 
2πr

66 
× 7/ 2×22 = r
33 × 7/22 =r
21/2  = r
10.5 = r

so the radius of the circle is 10.5 cm
Answered by hhhhhkhojkokko
17

Answer:

Step-by-step explanation:

The wire is in the shape of rectangle

length = 18 cm

breadth = 15 cm

now the wire is bent into a circle

so

perimeter of rectangle = circumference of the circle

2(l+b) = 2πr

2(18 +15)     =  2πr

2×33 = 2πr

66 = 2πr

66 × 7/ 2×22 = r

33 × 7/22 =r

21/2  = r

10.5 = r

so the radius of the circle is 10.5 cm

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