A wire in the shape of a rectangle of length 18cm and width 15cm is reshaped and bent in the form of a circle find the radius
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Answered by
261
The wire is in the shape of rectangle
length = 18 cm
breadth = 15 cm
now the wire is bent into a circle
so
perimeter of rectangle = circumference of the circle
2(l+b) = 2πr
2(18 +15) = 2πr
2×33 = 2πr
66 = 2πr
66 × 7/ 2×22 = r
33 × 7/22 =r
21/2 = r
10.5 = r
so the radius of the circle is 10.5 cm
length = 18 cm
breadth = 15 cm
now the wire is bent into a circle
so
perimeter of rectangle = circumference of the circle
2(l+b) = 2πr
2(18 +15) = 2πr
2×33 = 2πr
66 = 2πr
66 × 7/ 2×22 = r
33 × 7/22 =r
21/2 = r
10.5 = r
so the radius of the circle is 10.5 cm
Answered by
17
Answer:
Step-by-step explanation:
The wire is in the shape of rectangle
length = 18 cm
breadth = 15 cm
now the wire is bent into a circle
so
perimeter of rectangle = circumference of the circle
2(l+b) = 2πr
2(18 +15) = 2πr
2×33 = 2πr
66 = 2πr
66 × 7/ 2×22 = r
33 × 7/22 =r
21/2 = r
10.5 = r
so the radius of the circle is 10.5 cm
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