Question

A wire in the shape of a rectangle whose it's length is 40 cm and breadth is 22 CM if the same wire is rebent in the shape of a square what will be the measure of each side also find which shape enclosed more area

Answer 1

Answer:

perimeter of rectangle= 2(l+b)=2(40+22)=2(62)=124cm

square's perimeter will be 124 cm square side will perimeter/4

124/4= 31cm each side(arm)

area of rectangle = l*b=40*22=880cm²

area of square= side²=31*31=961cm²

so square is enclosing more area than rectangle.

Answer 2

Given:

Length of the rectangle = 40 cm

Breadth of the square = 22 cm

Then we will get:

Perimeter of the rectangle = Perimeter of the Square

2 (Length + Breadth) = 4 × side

2 (40 + 22) = 4 × side

2 (62) = 4 × side

124 = 4 × side

Side = 124/4

Side = 31 cm

So, Area of the rectangle = (Length × Breadth)

= 40 × 22

= 880 cm²

Area of square = side²

= 312

= 31 × 31

= 961 cm²

∴Square shaped wire encloses more area.