Question

A wire in the shape of a square of side 10 centimetre if the wire is bent into a rectangle of length 12 centimetre find its base with figure in closed more area and how much

Answer 1

Hello Friend!!! : )
Here Is The Answer:

perimeter of square = 4  side
                                = 4 x 10
                                = 40 cm
perimeter o rectangle = 2 [ l + b ]
40 = 2 [ 12 + b ]
40 = 24 + 2 b
40 - 24 = 2 b
16 = 2 b
b = 16 / 2
b = 8 cm

So, The breadth is 8 cm

Hope It Helps You!!!
Have A Good Day! ^_^

Answer 2

hiii!!!

here's ur answer...

perimeter of square=perimeter of rectangle

given the side of the square is 10cm.

perimeter of the square = side×4

= 10×4

= 40cm

therefore perimeter of the rectangle is 40cm.

length of the rectangle is 12cm.

=> 2(l+b) = 40cm

=> 2(12+b) = 40cm

=> 24+2b = 40cm

=> 2b = 40-24

=> 2b = 16

=> b = 16/2

=> b = 8cm

verification:-

perimeter of the rectangle = 2(l+b)

= 2(12+8)

= 2×20

= 40cm

hence verified

thus the breadth of the rectangle is 8cm.

now,

area of the square = side²

= 10×10

= 100cm²

area of the rectangle = l×b

= 12×8

= 96cm²

area of square is greater by = 100-96

= 4cm²

hope this helps u..!