A wire in the shape of rectangle of dimensions 10 cm by 8 cm is opened and then rebent to make a square. Find the measure of each side of the square.
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Answered by
2
length of a rectangle is 10cm
breadth is 8 cm
then this same wire is bent in a form of a square,so perimeter of square=perimeter of a rectangle
4a=2(l+b)
4a=2(10+8)
4a=36
a=9cm
Measure of each side is 9 cm.
breadth is 8 cm
then this same wire is bent in a form of a square,so perimeter of square=perimeter of a rectangle
4a=2(l+b)
4a=2(10+8)
4a=36
a=9cm
Measure of each side is 9 cm.
Answered by
6
Answer:
9 cm
Step-by-step explanation:
Since the rectangle and square are made of the same wire, their perimeters will be equal.
Given:
Length of rectangle = 10 cm
Breadth of rectangle = 8 cm
Thus, perimeter of rectangle:
2 ( l + b )
= 2 ( 10 + 8 )
= 2 ( 18 )
= 36 cm
Hence, perimeter of square is also 36 cm.
Let the side of the square be x.
Thus,
4 × x = Perimeter of the square
4 × x = 36
x = 9 cm
Hence, ANS = 9 cm
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