A wire in the shape of rectangle whose width is 22 cm is bent to form a square of side 31cm. Find the length of rectagle.Also find which shape encloses more area
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let a be side of square
w be width of rectangle
l be length of rectangle
since the length of wire is constant perimeter of square is equal to perimeter of rectangle
4a=2(l+b)
4(31)=2(l+22)
l=40
area of square =a^2=(31)^2=961
area of rectangle=lxb=40x22=880
square shape encloses more area
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Answer:
let a be side of square
w be width of rectangle
l be length of rectangle
since the length of wire is constant perimeter of square is equal to perimeter of rectangle
4a=2(l+b)
4(31)=2(l+22)
l=40
area of square =a^2=(31)^2=961
area of rectangle=lxb=40x22=880
square shape encloses more area
Step-by-step explanation:
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