Math, asked by nakul1044, 1 year ago

A wire in the shape of square of side 10cm if the wire is rebent into a rectangle of lenght 12cm find its breath which encloses more area the rectangle or the square

Answers

Answered by swapimamuni
5

Answer:

A square has all the sides of equal length.

So, Its perimeter =4*10cm=40cm.

According to question,

Perimeter of square=perimeter of rectangle

-> 40cm=2(l+b)

40=2(12+b)

20=12+b

8=b

Therefore, area of rectangle=l*b=12*8=96cm.

area of square=10*10=100 cm

So area enclosed by square is more than that of rectangle.




Answered by ItzzUnknown007
13

 \huge \purple {AnsWer}

Side of a square = 10cm

⠀⠀⠀Perimeter of square = 4 × S

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 4 × 10 = 40cm².

Perimeter of sq. = Perimeter of rectangle =40cm²

Perimeter of rectangle = 2 ( L + B )

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀40 = 2 ( 12 + B )

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀40 = 24 + 2B

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀40 - 24 = 2B

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀B =  \frac{16}{2}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀B = 8cm.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Area of sq. = S × S

⠀⠀⠀⠀⠀⠀⠀= ( 10 × 10 ) cm²

⠀⠀⠀⠀⠀⠀⠀= 100 cm²

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Area of rectangle = ( L × B ) sq. unit

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = ( 12 × 8 ) cm²

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 96 cm².

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Square has encloned more area by 4cm² .

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