Physics, asked by Ivae, 1 year ago

A wire increases it's length by 10^-3 of it's lenght when a stress of 10^8 is applied to it . What is it's Young Modulus of material of the wire .

Answers

Answered by rohit710
61
Heya........!!!!!

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Given in the question :-

• Stress => 10^8 N/m^2

• Longitudnal Strain => 10^-3

♦ Young Modulus => Y = Stress/Strain

Y =
 \frac{10 {}^{8} }{10 {}^{ - 3} }  \\  =  >  \:  \: 10 {}^{11}


Young Modulus => 10^11 N/m^2


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Answered by aristeus
12

Young's modulus will be 10^{11}N/m^2

Explanation:

Let the length of the of the wire is l

Then change in length \Delta l=10^{-3}l

So strain will be equal to =\frac{\Delta l}{l}=\frac{10^{-3}l}{l}=10^{-3}

Stress is given as stress =10^8N/m^2

We know the formula of young's modulus

Young's\ modulus=\frac{stress}{strain}=\frac{10^8}{10^{-3}}=10^{11}N/m^2

So young's modulus will be 10^{11}N/m^2

Learn more

A wire increases by 10 to the power minus 4 of its length when a stress of 1 into 10 to the power 8 Newton per metre square is applied on it what is Young's modulus of the material of the wire

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