A wire is 1.0 m long, 0.2 mm in diameter and has a resistance of 10 ohm calculate the resistivity of this material
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Length l = 1.0 m
Diameter d = 0.2 mm
So,
radius r = 0.1 mm = 1.0×10^(-4) m
Resistance R = 10 Ω
Let resistivity be ρ
Now,
R = ρ l/ASo,
ρ = (R×A)/l= R×π×r² /l= 10×(22/7)×[1.0×10^(-4)]² / 1.0
= 22×10^(-7) / 7
So,
ρ = 3.14 × 10^(-7) Ωm
i hope it will help you
regards
Diameter d = 0.2 mm
So,
radius r = 0.1 mm = 1.0×10^(-4) m
Resistance R = 10 Ω
Let resistivity be ρ
Now,
R = ρ l/ASo,
ρ = (R×A)/l= R×π×r² /l= 10×(22/7)×[1.0×10^(-4)]² / 1.0
= 22×10^(-7) / 7
So,
ρ = 3.14 × 10^(-7) Ωm
i hope it will help you
regards
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