A wire is 1.0 m long , 0.2mm in diameter and has a resistance of 10 ohms.Calculate the resistivity of the material ?a
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l=1m
r=0,2mm=0.0002m
R=2Ω
ρ=?
R=ρl/s
ρ=Rs/lρ s=r2π=(0.0002)2*3.14=1.256*10 (-7)
ρ=2Ω*1m/1.256*10(-7)
ρ=1.58 * 10(7)
r=0,2mm=0.0002m
R=2Ω
ρ=?
R=ρl/s
ρ=Rs/lρ s=r2π=(0.0002)2*3.14=1.256*10 (-7)
ρ=2Ω*1m/1.256*10(-7)
ρ=1.58 * 10(7)
Answered by
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Hey there!
Given,
Length(l) = 1 m
Diameter(d) = 0.2 mm
Radius(r) = 0.1 mm or 0.001 m
Resistance(R) = 10 Ω
Now,
Area =πr²
= 3.14 × 0.001 × 0.001
= 0.00000314 m²
We know,
Resistivity = RA/l
= 10 × 0.00000314/1
= 0.0000314 Ω m
= 3.14×10^-7 Ω m
Hope It Helps You!
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