A wire is 1 m long ,0.2 mm in diameter and has a resistance of 10 ohm.calculate the resistivity of its material
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Answered by
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The formula is R= pro* L / A
So we have to find the resistivy pro= R*A/L
So we put the values then the answer will be 1
So we have to find the resistivy pro= R*A/L
So we put the values then the answer will be 1
nitin207:
but the answer that given in book is 31.4×10^-8 ohm meter
Yes by witting A = pie* rsquare then the answer will come
Answered by
1
Here , it is Given that:
l=1m ,d=0.2mm=>r=0.1mm and R=10 ohm
by using the formula,
R= p౹/ A
= p౹/ πr²
therefore, p= Rπr²/l
= 10× 3.14×( 0.1× 10 -³)²
= 10× 3.14× 0.1×0.1× 10 to the power -6
= 0.314× 10 to the power-6
= 3.14× 10 to the power-7 ohm- m
hence, the resistivity of the conductor is 3.14× 10 to the power-7 ohm- m
l=1m ,d=0.2mm=>r=0.1mm and R=10 ohm
by using the formula,
R= p౹/ A
= p౹/ πr²
therefore, p= Rπr²/l
= 10× 3.14×( 0.1× 10 -³)²
= 10× 3.14× 0.1×0.1× 10 to the power -6
= 0.314× 10 to the power-6
= 3.14× 10 to the power-7 ohm- m
hence, the resistivity of the conductor is 3.14× 10 to the power-7 ohm- m
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