A wire is 1m long ,0.2mm in diameter and has resistance of 10 ohm.calculate its resistivity
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Answered by
10
given-- length(L)=1m
radius(r)=0.1mm=10^-4[since diameter is 0.2mm]["^" is used to show degree of power]
resistance(R)=10 ohm
area = 3.14 x r x r =3.14 x 10^-4 x 10^-4 = 3.14 x 10^-8 m^2
Resistivity = ( R x area)/L
= (10 x 3.14 x 10^-8)/1
= 3.14 x 10^-7 ohm
PS ---- i think this is the answer but i too am a beginner and am just going by the formula given in my book. let me know if this is the correct answer.
radius(r)=0.1mm=10^-4[since diameter is 0.2mm]["^" is used to show degree of power]
resistance(R)=10 ohm
area = 3.14 x r x r =3.14 x 10^-4 x 10^-4 = 3.14 x 10^-8 m^2
Resistivity = ( R x area)/L
= (10 x 3.14 x 10^-8)/1
= 3.14 x 10^-7 ohm
PS ---- i think this is the answer but i too am a beginner and am just going by the formula given in my book. let me know if this is the correct answer.
RakaChoudhury:
the answer should be 3.14 x 10-7 ohm metre
Answered by
11
HI there !!
Length = l = 1 m
Diameter = 0.2mm
Radius = r = 0.1 mm = 0.0001 m
Area = A =πr² = 3.14 × 0.0001 × 0.0001 = 3.14×10⁻⁸ m²
Resistance = R = 10 Ω
Resistivity = ρ = RA / l
= 10 × 3.14×10⁻⁸ / 1
= 31.4×10⁻⁸ Ω m
Length = l = 1 m
Diameter = 0.2mm
Radius = r = 0.1 mm = 0.0001 m
Area = A =πr² = 3.14 × 0.0001 × 0.0001 = 3.14×10⁻⁸ m²
Resistance = R = 10 Ω
Resistivity = ρ = RA / l
= 10 × 3.14×10⁻⁸ / 1
= 31.4×10⁻⁸ Ω m
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