Question

.  A wire is 1m long, 0.2mm in diameter and has resistance of 10Ω. Calculate its resistivity.​

Answer 1

Answer:

The resistivity of the conductor is $\bf 3.14\times10^{-7} \Omega$

Explanation:

Given -

Length(l) = 1 m

Diameter(d) = 0.2 mm

Radius(r) = 0.1 mm or 0.001 m

Resistance(R) = 10 Ω

To Find -

The resistivity.​

Solution -

As we know,

$\bigstar\;\boxed{\sf Area =\pi r^2}}$

So,

⇒ 3.14 × 0.001 × 0.001

⇒ 0.00000314 m²

As we know,

$\bigstar\;\boxed{\sf Resistivity = \dfrac{RA}{l}}}$

$\sf\\ \\\implies 10 \times \dfrac{0.00000314}{1}\\ \\ \\ \implies 0.0000314 \Omega m\\ \\ \implies 3.14\times10^{-7} \Omega m$

Therefore,

The resistivity of the conductor is $\bf 3.14\times10^{-7} \Omega$

Answer 2

Explanation:

3.14 × 10-7 π

hope it will help you