A wire is 1m long ,0.2mm in diameter and has resistance of 10 ohm.calculate its resistivity
Answers
Answered by
2
As we know that,
R =¶ L/A
where ¶ is resistivity
A is πr^2
Here d is 0.2 mm then r will be 0.1 mm which is equal to 0.001m.
l is 1m
R is 10 ohm
¶ = RA/l
Substitute values of R,A and l to calculate resistivity.
Hope you get your answer.
R =¶ L/A
where ¶ is resistivity
A is πr^2
Here d is 0.2 mm then r will be 0.1 mm which is equal to 0.001m.
l is 1m
R is 10 ohm
¶ = RA/l
Substitute values of R,A and l to calculate resistivity.
Hope you get your answer.
Answered by
0
Hey there!
Given,
Length(l) = 1 m
Diameter(d) = 0.2 mm
Radius(r) = 0.1 mm or 0.001 m
Resistance(R) = 10 Ω
Now,
Area =πr²
= 3.14 × 0.001 × 0.001
= 0.00000314 m²
We know,
Resistivity = RA/l
= 10 × 0.00000314/1
= 0.0000314 Ω m
= 3.14×10^-7 Ω m
Hope It Helps You!
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