A wire is 1m long, 0.2mm in diameter and has resistance of 10Ω. Calculate its resistivity.
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According to the question,
l=1m ,
d=0.2mm
→r=0.1mm and
R=10 Ω
by using the formula,
R= p౹/ A
= p౹/ πr²
therefore, p= Rπr²/l
= 10× 3.14×( 0.1× 10 -³)²
= 10× 3.14× 0.1×0.1× 10 to the power -6
= 0.314× 10 to the power-6
= 3.14× 10 to the power-7 Ω- m
Hence, the resistivity of the conductor is 3.14× 10 to the power-7 Ω- m
Hope it will help you.
l=1m ,
d=0.2mm
→r=0.1mm and
R=10 Ω
by using the formula,
R= p౹/ A
= p౹/ πr²
therefore, p= Rπr²/l
= 10× 3.14×( 0.1× 10 -³)²
= 10× 3.14× 0.1×0.1× 10 to the power -6
= 0.314× 10 to the power-6
= 3.14× 10 to the power-7 Ω- m
Hence, the resistivity of the conductor is 3.14× 10 to the power-7 Ω- m
Hope it will help you.
xcrehmansir:
cud u explain the 4rth last line se
Which one?
= 10× 3.14× 0.1×0.1× 10 to the power -6 how did -6 come
-³)².
oh ok thaks
*thanks
Thanks Rohan for help him out with the explanation
Welcome Deb
its her
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