a wire is (24×-5)metre long and it is attached to another wire of length (15×+7) metre a wire of length(17×-2)metre is cut from the total length of the wire.how much wire is left?
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Step-by-step explanation:
{(-120)+(105)-(-34)}m
=(139-120)m
=19m wire is left
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Length of wire 1 = 24x-5 = -120m
Length of wire 2 = 15 x 7 = 105m
Length of wire 3 = 17 x -2 = -34m
According to the question wire 1 and wire 2 are attached so
Total length = Length of wire 1 + length of wire 2 = -120 +105 = -15m
Now it is said that wire 3 is cut off from the total length so
length of wire 3 - total length = -34 - ( -15 )
= -34 + 15 = -19 m
Length of wire 2 = 15 x 7 = 105m
Length of wire 3 = 17 x -2 = -34m
According to the question wire 1 and wire 2 are attached so
Total length = Length of wire 1 + length of wire 2 = -120 +105 = -15m
Now it is said that wire 3 is cut off from the total length so
length of wire 3 - total length = -34 - ( -15 )
= -34 + 15 = -19 m
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