A wire is (7x --3) m long. A length of (3x – 4)m is cut for use. Now, answer the following questions : (a) How much wire is left? (b) If this left out wire is used as a side for making an equilateral triangle, what is the perimeter of the triangle so formed?
Answers
Answer:
(a)
(3x−4) metres wire is cut from (7x−3) metres long wire.
So, the remaining length of the wire
=(7x−3)−(3x−4)
=7x−3−3x+4
=(7x−3x)+(−3+4)
=4x+1
Hence, the length of wire left is (4x+1) metres.
(b)
Step 1: Find the remaining length of the wire
(3x−4) metres wire is cut from (7x−3) metres long wire.
So, the remaining length of the wire
=(7x−3)−(3x−4)
=7x−3−3x+4
=(7x−3x)+(−3+4)
=4x+1
Hence, the length of wire left is (4x+1) metres.
Step 2:Find the length of each side of the triangle formed from the left-out wire
Perimeter of an equilateral triangle =3× side
Therefore, 3× side =4x+1
side =
3
4x+1
(dividing by 3 on both sides)
Hence, the length of each side of the triangle so formed is
3
4x+1
metres
Answer: otal length of wire=(7x-3)
length of wire cut=(3x-4)
7x-3-(3x-4)
=7x-3-3x+4
=7x-3x-3+4
=4x+1
4x+1 meter is the length of wire that is left
now equilateral triangle has all three sides equal
therefore
4x=1/3 meter will be the length of each side of the equilateral triangle formed