Math, asked by raghav805701, 1 year ago

a wire is (7x-3) metres long. a length of (3x-4) is cut for use. How much wire is left? if the left wire is used to form an equilateral triangle then what will be the length of each of it's sides?

Answers

Answered by 22072003
68
Given length of the wire = ( 7x - 3 ) m

Length of Wire used = ( 3x - 4 ) m

<b>Wire left –</b>

= Original length of wire - Length of wire used

= ( 7x - 3 ) - ( 3x - 4 )

= 7x - 3 - 3x + 4

= 4x - 7

Hence, <b><u>( 4x - 7 ) m of wire is left.</b></u>

Now, Length of wire which is left is used to make an equilateral triangle.

So, the wire length will be equal to <b>perimeter</b> of the triangle.

As we know that the length of side of equilateral triangle is same.

Let, each side of equilateral triangle = 'a' cm

<u>Perimeter of equilateral triangle = 3 ( a ) </u>

•°•

4x - 7 = 3 ( a )

a = ( 4x - 7 ) / 3

Hence, <b><u>Side of equilateral triangle is ( 4x - 7 ) / 3 m.</b></u>
Answered by vaidehigupta00
85

Answer:

total length of wire=(7x-3)

length of wire cut=(3x-4)

7x-3-(3x-4)

=7x-3-3x+4

=7x-3x-3+4

=4x+1

4x+1 meter is the length of wire that is left

now equilateral triangle has all three sides equal

therefore

4x=1/3 meter will be the length of each side of the equilateral triangle formed

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