a wire is (7x-3) metres long. a length of (3x-4) is cut for use. How much wire is left? if the left wire is used to form an equilateral triangle then what will be the length of each of it's sides?
Answers
Answered by
68
Given length of the wire = ( 7x - 3 ) m
Length of Wire used = ( 3x - 4 ) m
= Original length of wire - Length of wire used
= ( 7x - 3 ) - ( 3x - 4 )
= 7x - 3 - 3x + 4
= 4x - 7
Hence,
Now, Length of wire which is left is used to make an equilateral triangle.
So, the wire length will be equal to of the triangle.
As we know that the length of side of equilateral triangle is same.
Let, each side of equilateral triangle = 'a' cm
•°•
4x - 7 = 3 ( a )
a = ( 4x - 7 ) / 3
Hence,
Length of Wire used = ( 3x - 4 ) m
= Original length of wire - Length of wire used
= ( 7x - 3 ) - ( 3x - 4 )
= 7x - 3 - 3x + 4
= 4x - 7
Hence,
Now, Length of wire which is left is used to make an equilateral triangle.
So, the wire length will be equal to of the triangle.
As we know that the length of side of equilateral triangle is same.
Let, each side of equilateral triangle = 'a' cm
•°•
4x - 7 = 3 ( a )
a = ( 4x - 7 ) / 3
Hence,
Answered by
85
Answer:
total length of wire=(7x-3)
length of wire cut=(3x-4)
7x-3-(3x-4)
=7x-3-3x+4
=7x-3x-3+4
=4x+1
4x+1 meter is the length of wire that is left
now equilateral triangle has all three sides equal
therefore
4x=1/3 meter will be the length of each side of the equilateral triangle formed
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