Question

a wire is (7x-3) metres long a length of (3x-4) metres is cut for use how uch wire is left ??
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Answer 1

Question:-

A wire is (7x−3) meter long. A length of (3x−4) meters is cut for use. Now, answer the following questions:

(a) How much wire is left?

(b) If this left out wire is used for making an equilateral triangle. What is the length of each side of the triangle so formed?

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Total length of the wire = 7x-3 mts

Length of the wire that is cut = 3x-4 m

Length of the wire left = 7x-3 - 3x-4

= 7x-3-3x+4

= 4x+1 m

Now, perimeter of equilateral ∆ = 4x+1 m

⇒3s

= 4x+1

where s = length of each side of an equilateral ∆

⇒s = 4x+13 mLength of each side of an equilateral ∆ =4x+13 m

Answer 2

Answer

total length of wire=[7x-3]

length of wire cut=[3x-4]

7x-3-[3x-4]

=7x-3-3x+4

=7x-3x-3+4

=4x+1

4x+1 meter is the length of wire that is left

now equilateral triangle has all three sides equal

therefore

4x=1\3 meter will be the lenght of each side of equilateral triangle formed.

hope this is helpful .